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Configuration = 102
cycles = (10 5 2 9 3)(8 6 1 7 4)

a = 1, b = 4, c = 6
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cycles = (10 2 4 9 5)(8 6)(7 1)(3)

a = 2, b = 4, c = 10
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cycles = (10 7 3)(9)(8)(6 4)(5 1)(2)

a = 4, b = 5, c = 6
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cycles = (10 7 3)(9)(8)(6 1 4)(5)(2)

a = 1, b = 4, c = 6
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cycles = (10 7 5)(9)(8)(6)(4)(3)(2)(1)